用API函数打开MSCommonDialog对话框

在模块中加入:
Declare Function GetOpenFileName Lib "comdlg32.dll" Alias "GetOpenFileNameA" (pOpenfilename As- OPENFILENAME) As Long
Type OPENFILENAME
lStructSize As Long
hwndOwner As long
hInstance As Long
lpstrFilter As String
lpstrCustomFilter As String
nMaxCustFilter As Long
nFilterIndex As Long
lpstrFile As String
nMaxFileTitle As Long
lpstrInitialDir As String
lpstrTitle As String
flags As Long
nFileOffset As Integer
nFileExtension As Integer
lpstrDefExt As String
lCustData As Long
lpfnHook As Long
lpTemplateName As String
End Type
然后在Form窗体上加一个文本框和按钮Caption属性为"打开".双击按钮加入下列代码:
Private Sub Command1_Click()
Dim ofn As OPENFILENAME
Dim rtn As String
ofn.lStructSize=len(ofn)
ofn.hwndOwner=Me.hWnd
ofn.hInstance=App.hInstance
ofn.lpstrFilter="所有文件"
ofn.lpstrFile=Space(254)
ofn.nMaxFileTitle=255
ofn.lpstrInitialDir=app.path
ofn.lpstrTitle="打开文件"
ofn.flags=6148
rtn=GetOpenFileName(ofn)
If rtn>=1 then
Text1.Text=ofn.lpstrFile
Else
Text1.Text="Cancel Was Pressed"
End If
End Sub
运行程序,点击"打开"按钮就会弹出打开文件对话框.选中任何文件再确定,Text1.Text就会显示任何文件名.