如何将SQL全文检索中的“干扰词”去除
“干扰词”包括以下内容,然后调用:remove_noise_word()即可
<SCRIPT LANGUAGE=javascript>
<!--
noise_word_list_ch = new Array("?","about","$","1","2","3","4","5","6","7","8","9","0","_",
"a","b","c","d","e","f","g","h","i","j","k","l","m","n","o",
"p","q","r","s","t","u","v","w","x","y","z","after","all","also",
"an","and","another","any","are","as","at","be","because","been",
"before","being","between","both","but","by","came","can","come",
"could","did","do","each","for","from","get","got","had","has",
"have","he","her","here","him","himself","his","how","if","in","into",
"is","it","like","make","many","me","might","more","most","much","must",
"my","never","now","of","on","only","or","other","our","out","over","said",
"same","see","should","since","some","still","such","take","than","that",
"the","their","them","then","there","these","they","this","those","through",
"to","too","under","up","very","was","way","we","well","were","what","where",
"which","while","who","with","would","you","your",
"的","一","不","在","人","有","是","为","以","于","上","他","而","后","之","来",
"及","了","因","下","可","到","由","这","与","也","此","但","并","个","其","已",
"无","小","我","们","起","最","再","今","去","好","只","又","或","很","亦","某",
"把","那","你","乃","它");
function trim_str_key(inputVal){
inputStr = inputVal.toString()
while ((inputStr.charAt(inputStr.length - 1) == " ") (inputStr.charAt(0) == " ")){
//如果最右边为空格则删去
if (inputStr.charAt(inputStr.length - 1) == " "){
inputStr = inputStr.substring(0,inputStr.length - 1)
}
//如果最左边为空格则删去
if (inputStr.charAt(0) == " "){
inputStr = inputStr.substring(1,inputStr.length)
}
}
return inputStr
}
function is_ch_noise_word(str_key){
var key_word = trim_str_key(str_key);
key_word = key_word.toLowerCase();
var listlength=noise_word_list_ch.length;
var tmp_str = "";
for(i=0;i<listlength;i++){
tmp_str = noise_word_list_ch[i]
if(tmp_str==key_word){
return true;
}
}
return false;
}
function remove_noise_word(str_source){
var tmp_str = "";
var ch = "";
var str_out = "";
var i = 0;
str_source = trim_str_key(str_source);
var str_source_length = str_source.length;
if(str_source_length == 0){
return str_out;
}
for (i=0;i < str_source_length; i++){
ch = str_source.charAt(i);
if(ch==" "){ //如果为空格则表示是下一个关键词
if(!(is_ch_noise_word(tmp_str))){ //不是干扰词就输出
if(tmp_str!=" "){ //防止连续的两个空格
str_out = str_out + tmp_str + " ";
}
}
tmp_str = "";
}
else{
tmp_str = tmp_str + ch;
}
}
str_out = str_out + tmp_str;
return trim_str_key(str_out);
}
//下面是一个测试
//var abc = "av n";
//var nnnn = remove_noise_word(abc);
//alert(nnnn);
//-->
</SCRIPT>